1. \(_{x\to
-1}^{\lim }\,\frac{{{x}^{2}}+2x+1}{2{{x}^{2}}-x-1}\)
jawab:
1.
\( _{x\to -1}^{\lim }\,\frac{{{x}^{2}}+2x+1}{2{{x}^{2}}-x-1}\)
\( _{x\to
-1}^{\lim }\,\frac{{{x}^{2}}+2x+1}{2{{x}^{2}}-x-1}=\frac{_{x\to -1}^{\lim
}\left( {{x}^{2}}+2x+1 \right)}{_{x\to -1}^{\lim }\left( 2{{x}^{2}}-x-1
\right)}\,=\frac{{{\left(
-1 \right)}^{2}}+2.\left( -1 \right)+1}{2.{{\left( -1 \right)}^{2}}-\left( -1
\right)-1}\,=\frac{0}{3}\,=0
\)
