Soal Dan Pembahasan Limit Fungsi Aljabar

1. \(_{x\to -1}^{\lim }\,\frac{{{x}^{2}}+2x+1}{2{{x}^{2}}-x-1}\)

jawab: 

1.    \( _{x\to -1}^{\lim }\,\frac{{{x}^{2}}+2x+1}{2{{x}^{2}}-x-1}\)

\(  _{x\to -1}^{\lim }\,\frac{{{x}^{2}}+2x+1}{2{{x}^{2}}-x-1}=\frac{_{x\to -1}^{\lim }\left( {{x}^{2}}+2x+1 \right)}{_{x\to -1}^{\lim }\left( 2{{x}^{2}}-x-1 \right)}\,=\frac{{{\left( -1 \right)}^{2}}+2.\left( -1 \right)+1}{2.{{\left( -1 \right)}^{2}}-\left( -1 \right)-1}\,=\frac{0}{3}\,=0 \)